Arts & Humanities
Beauty & Style
Business & Finance
Cars & Transportation
Computers & Internet
Consumer Electronics
Dining Out
Education & Reference
Entertainment & Music
Environment
Family & Relationships
Food & Drink
Games & Recreation
Health
Home & Garden
Local Businesses
News & Events
Pets
Politics & Government
Pregnancy & Parenting
Science & Mathematics
Social Science
Society & Culture
Sports
Travel
Yahoo Products

15 years ago

Just a technicality question...
Two particles move in the x-y plane. For t>=0, the position of particle A is x = (t-2)^2 and y = t-2 and the position of particle B is x = 3/2t - 2 and y = 3/2t - 4. At what time do the particles collide?
I have already translated both equations into rectangular form and found that they intersect at the (x,y) point (4,2). Is this the answer I should give for "At what time do the particles collide?"? It doesn't seem to make sense with the question, but maybe that's just me...

Top 1 Answers

15 years ago

Favorite Answer
For t>=0,
the position of particle A is
x1 = (t-2)^2 and y1 = t-2
and the position of particle B is
x2 = 3/2t - 2 and y2 = 3/2t - 4.
At what time do the particles collide?
Find t such that
x1=x2: (t-2)^2 = 3/2t - 2 or t^2 - 4t + 4 = 3/2t -2
t^2 -5.5t + 6 = 0
( t - 1.5) ( t - 4) = 0 ` ` ` ` or t = 1.5 or 4
and
y1=y2: t-2 = 3/2t - 4. or 0.5t = 2 or t =4
so at t = 4, the two particles collide at
x1=x2= 4
y1=y2= 2

0

Questions about braces. & Insurance!?!? please answer (:?Finanancial Aid for doctrate students in MIT and Stanford for Aerospace?What do you think about whats going on between Israel and Palestine?Anyone going to be joining World of Warcraft?second life??Something For Grandpa..?Are there any Finnish restaurants/bakery's In NY, NJ, or anywhere near that area?what is the hypothesis of HIV?Could atheism be considered a cult?Why are the Democrats so hung up on race?