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15 years ago

A Saucerful of Secrets

HELP me pleaaaaaaaaaaase?

A block of mass 3.7 kg is resting on a horizontal surface with a static coefficient of friction, µ=1.3. A spring with a constant 470 N/m is attached to the block and someone pulls on the other end of the spring. By how much does the spring extend before the block begins to move? g=9.81m/s2.

Top 2 Answers

15 years ago

teddy boy

Favorite Answer

The maximum static friction, Fmax = μsFn = 1.3(3.7)(9.8) Fmax = 47.1 N. From Hooke's Law: F = ks, where F is the applied tension force, k is the constant, and s is the elongation. For this problem, for the block to start moving, F = Fmax. Hence, ks = 47.1 s = 47.1/470 s = .1 m or 10 cm ANS teddy boy

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15 years ago

nyphdinmd

The block with move when the force exerted by the spring equals the force of static friction: kx = u*N = u*mg Solve for x x = umg/k = 1.3*3.7*9.8/470 = 0.100 m

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