14 years ago
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Help with area please.?

How to find the area of a rhombus with just the diagonals. There is a rhombus and the diagonals are intersecing each other forming 4 triangles and there are 2 length with 9m,and 2 with 10.5m. I just want to know how to solve that. There's no measurement outside the rhombus, just the measurement for the diagonals. If you could be so kind to explain this.
Top 3 Answers
14 years ago
mlam18
Favorite Answer
9 * 10.5 = 94.5 sq m This is the area of a rectangle formed by the two diagonals, which is the same as length times width. But the rhombus is the diamond shape just inside the rectangle. So the area of the rhombus is really 1/2 of the rectangle. Area = 0.5 * 94.5 = 47.25 sq m
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14 years ago
Striker
by definition of a rhombus, the area is given by 1/2 (diagonal1 x diagonal2). but if you dont want that formula...consider the 2 bigger triangles formed, not 4. the two intersecting lines of a rhombus is perpendicular to each other. knowing the area of triangle, 1/2 BH, the area of 1 triangle is 1/2 x 10.5 x 4.5. take it from here..
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14 years ago
Twiggy
The diagonals of a rhombus bisect each other at right angles, so you have four right angled triangles in which you know the base and the vertical height... Hope this helps, Twiggy.
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