14 years ago
cbaxter2010

How to calculate mass given solubility constants?

Calculate the mass (g) of Pb3(AsO4)2 that will dissolve in 400 mL of 0.211 M Pb(NO3)2 solution. The equation represents the solubility process. Pb3(AsO4)2 (s) 3 Pb^2+ (aq) + 2 AsO4^3- (aq) Ksp = 4.0 x 10^-38 Molar Mass Pb3(AsO4)2 = 899.44
Top 1 Answers
14 years ago
Dr.A
Favorite Answer
4.0 x 10^-38 = [Pb2+]^3[AsO43-]^2 = = (3x+ 0.211)^3( 2x)^2 x = 1.06 x 10^-36 M 1.06 x 10^-36 mol/L x 0.400 L x 899.44 g/mol =3.8 x 10^-34 g
0